-20x=-16.1x^2+300

Solution for -20x=-16.1x^2+300 equation:

-20x=-16.1x^2+300

We move all terms to the left:

-20x-(-16.1x^2+300)=0

We get rid of parentheses

16.1x^2-20x-300=0

a = 16.1; b = -20; c = -300;
Δ = b2-4ac
Δ = -202-4·16.1·(-300)
Δ = 19720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19720}=\sqrt{4*4930}=\sqrt{4}*\sqrt{4930}=2\sqrt{4930}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{4930}}{2*16.1}=\frac{20-2\sqrt{4930}}{32.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{4930}}{2*16.1}=\frac{20+2\sqrt{4930}}{32.2}
$